How is -1.0 volts CSE converted to an Ag/AgCI reference electrode?

Prepare for the NACE CP1 Tester Exam with our quiz. Access flashcards and multiple choice questions, each with hints and explanations. Ace your exam!

Multiple Choice

How is -1.0 volts CSE converted to an Ag/AgCI reference electrode?

Explanation:
To convert a given potential from a Copper/Copper Sulfate Electrode (CSE) to a silver/silver chloride (Ag/AgCl) reference electrode, specific conversion factors must be applied. The CSE is typically around +0.1 volts against a standard hydrogen electrode (SHE), while the Ag/AgCl reference is around +0.197 volts against the same SHE at standard conditions. When starting with a potential of -1.0 volts CSE, the conversion process involves determining how that value translates into the potential of an Ag/AgCl reference. 1. First, you note that -1.0 volts CSE equates to approximately -1.1 volts against SHE (considering that CSE is +0.1 volt). 2. Then, you translate this voltage to Ag/AgCl by using the known value of Ag/AgCl relative to SHE, which is +0.197 volts. 3. Therefore, the equation would be: -1.1 volts (CSE) + 0.197 volts (Ag/AgCl reference) results in about -0.903 volts. 4. When taking into account the typical reference voltage of -0.850 volts against

To convert a given potential from a Copper/Copper Sulfate Electrode (CSE) to a silver/silver chloride (Ag/AgCl) reference electrode, specific conversion factors must be applied. The CSE is typically around +0.1 volts against a standard hydrogen electrode (SHE), while the Ag/AgCl reference is around +0.197 volts against the same SHE at standard conditions.

When starting with a potential of -1.0 volts CSE, the conversion process involves determining how that value translates into the potential of an Ag/AgCl reference.

  1. First, you note that -1.0 volts CSE equates to approximately -1.1 volts against SHE (considering that CSE is +0.1 volt).

  2. Then, you translate this voltage to Ag/AgCl by using the known value of Ag/AgCl relative to SHE, which is +0.197 volts.

  3. Therefore, the equation would be:

-1.1 volts (CSE) + 0.197 volts (Ag/AgCl reference) results in about -0.903 volts.

  1. When taking into account the typical reference voltage of -0.850 volts against
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy