What is the current in a circuit with a 30 A/50 mV shunt and a voltage drop of 10 mV?

To determine the current in a circuit using a shunt resistor, you can utilize the relationship between the shunt's rated current, its voltage drop, and the actual measurement. In this case, the shunt is rated for 30 A at a voltage drop of 50 mV. This means that for every 30 A of current, a voltage drop of 50 mV will occur across the shunt.

To find the current corresponding to a voltage drop of 10 mV, we can set up a proportional relationship. The voltage drop measured (10 mV) can be compared to the rated voltage drop (50 mV) in order to find the corresponding current.

The proportionality can be expressed as:

[ \text{Current} = \frac{\text{Voltage drop measured}}{\text{Voltage drop rated}} \times \text{Rated current} ]

Substituting in the known values:

[ \text{Current} = \frac{10 \text{ mV}}{50 \text{ mV}} \times 30 \text{ A} ]

This simplifies to:

[ \text{Current} = 0.2 \times 30 \text{ A}